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Standard XII

Chemistry

Nernst Equation

Equal volumes...

Question

Equal volumes of $0.015 M$ $C H_{3} C O O H$ & $0.015 M$ $N a O H$ are mixed together. What would be molar conductivity of mixture if conductivity of $C H_{3} C O O N a$ is $6.3 \times 10^{- 4} S c m^{- 1}$ ?

8.4 S c m^{2} m o l^{- 1}

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84 S c m^{2} m o l^{- 1}

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4.2 S c m^{2} m o l^{- 1}

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42 S c m^{2} m o l^{- 1}

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Solution

The correct option is C $84 S c m^{2} m o l^{- 1}$
$C H_{3} C O O H + N a O H$ $\to C H_{3} C O O N a$
0.015 0.015 $-$
$-$ $-$ 0.0075M (after mixing)

$∴$ $Λ m$ $=$ $(\frac{6.3 \times 10^{- 4} \times 1000}{0.0075})$ $=$ $(\frac{K \times 1000}{M})$ $=$ $84 S c m^{2} m o l^{- 1}$

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Similar questions

Q. Molar conductivities at infinite dilution of

N a C l

H C l

and

C H_{3} C O O N a

are 126.4, 425.9 and 91.0

S c m^{2} m o l^{- 1}

respectively. Molar conductivity for

C H_{3} C O O H

will be:

The molar conductances of HCl, NaCl and $C H_{3} C O O N a$ are 426, 126 91 $Ω^{- 1} c m^{2} m o l^{- 1}$ respectively. The molar conductances of $C H_{3} C O O H$ is :

Q. The molar conductivity of

N a C l, H C l

and

C H_{3} C O O N a

at infinite dilution are

126.45

426.16

and

91 S c m^{2} m o l^{- 1}

respectively. The molar conductivity of

C H_{3} C O O H

at infinite dilution is:

Q. A conductivity of

0.001 M N a_{2} S O_{4}

solution is

2.6 \times 10^{- 4} S c m^{- 1}

and increase to

7 \times 10^{- 4} S c m^{- 1}

, when the solution is saturated with

C a S O_{4}

. The molar conductivities of

N a

and

C a^{+ 2}

are

50

and

120 S c m^{2} m o l e^{- 1}

, respectively. Neglect conductivity of used water. What is the solublity product of

C a S O_{4}

The conductivity of $0.001 M$ $N a_{2} S O_{4}$ solution is $2.6 \times 10^{- 4} {S cm}^{- 1}$ and increases to $7 \times 10^{- 4} {S cm}^{- 1}$ , when the solution is saturated with $C a S O_{4}$ . The molar conductivity of $N a^{+}$ and $C a^{2 +}$ are $50$ and $120 {S cm}^{2} {mol}^{- 1}$ , respectively. Neglect the conductivity of water, find the solubility product of $C a S O_{4}$ .

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Equal volumes of 0.015M CH3COOH & 0.015M NaOH are mixed together. What would be molar conductivity of mixture if conductivity of CH3COONa is 6.3×10−4Scm−1?

The correct option is C 84 Scm2mol−1CH3COOH+NaOH →CH3COONa 0.015 0.015 − − − 0.0075M (after mixing)∴ Λm = (6.3×10−4×10000.0075) = (K×1000M) = 84 Scm2mol−1

Equal volumes of $0.015 M$ $C H_{3} C O O H$ & $0.015 M$ $N a O H$ are mixed together. What would be molar conductivity of mixture if conductivity of $C H_{3} C O O N a$ is $6.3 \times 10^{- 4} S c m^{- 1}$ ?

The correct option is C $84 S c m^{2} m o l^{- 1}$
$C H_{3} C O O H + N a O H$ $\to C H_{3} C O O N a$
0.015 0.015 $-$
$-$ $-$ 0.0075M (after mixing)

$∴$ $Λ m$ $=$ $(\frac{6.3 \times 10^{- 4} \times 1000}{0.0075})$ $=$ $(\frac{K \times 1000}{M})$ $=$ $84 S c m^{2} m o l^{- 1}$