A solution prepared by mixing $200 m l$ of $0.025 M$ $C a C l_{2}$ and $400 m l$ of $0.15 M$ $N a_{2} S O_{4}$ ? Given $K_{s p}$ of $C a S O_{4}$ = $2.4 \times 10^{- 5}$ Then

K_{s p}

C a S O_{4}

4 \times 10^{- 12} . C a S O_{4}

is precipitated on mixing equal volumes of the following solutions.

Q. When equal volumes of the following solutions are mixed, precipitation of

A g C l (K_{s p} = 1.8 \times 10^{- 10})

will occur only with

Join BYJU'S Learning Program

Equal volumes of 0.02 M CaCl2 and 0.04 M Na2SO4 are mixed. Will a precipitate form? (Ksp of CaSO4=2.4×10−5)

The correct option is D No CaCl2+Na2SO4⟶CaSO4+2NaClMillimoles added 0.02 V 0.0004 x V 0 0Suppose V mL of both are mixed,∴[Ca2+]=0.02V2V and [SO2−4]=0.0004V2V∴[Ca2+][SO2−4]=0.02V2V×0.0004V2V=2×10−6Thus, [Ca2+][SO2−4] in solution <KspSo, precipitate will not form.

Equal volumes of $0.02 M$ $C a C l_{2}$ and $0.04 M$ $N a_{2} S O_{4}$ are mixed. Will a precipitate form?
$(K_{s p}$ of $C a S O_{4} = 2.4 \times 10^{- 5})$