Equation - $4 x - 5 y + 33 = 0 - (1)$
$20 x - 9 y = 107 - (2)$
Find $¯ ¯ ¯ x$ & $¯ ¯ ¯ y$

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Solution

$4 x - 5 y = - 33$ ......(1)
Multiplying by $5$ , we get
$20 x - 25 y = - 165$ ......(1)
$20 x - 9 y = 107$ ......(2)

On subtracting equation(2) from equation (1), we get
$- 16 y = - 58$
$y = \frac{29}{8},$

On substituting this value in equation (1), we get
$4 x - \frac{5 \times 29}{8} = - 33$

$4 x = \frac{145}{8} - 33$

$9 y = \frac{145 - 264}{8}$

$y = - \frac{119}{8} .$

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$4 x - 5 y + 33 = 0$
$20 x - 9 y = 107$
Find $x$ and $y$ .

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20 x - 9 y - 107 = 0

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