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Question

Equation of the line passing through (1, 2) and parallel to the line y=3x1 is .


A
y+2=x+1
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B
y+2=3(x+1)
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C
y2=3(x1)
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D
y2=x1
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Solution

The correct option is C y2=3(x1)

We are given the point, all we have to do is to find the slope.

From the equation y=3x1

the slope of the line parallel to this line will be 3.

Therefore the required equation which passes through (1, 2) and with gradient as 3, is
y – 2 = 3 (x – 1)
y - 2 = 3x - 3
3x - y + 1 = 0


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