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Question

Equation of the parabola having focus (3,2) and Vertex (−1,2) is

A
(x+1)2=16(y2)
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B
(x1)2=16(y+2)
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C
(y2)2=16(x+1)
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D
(y+2)2=16(x1)
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Solution

The correct option is C (y2)2=16(x+1)
Equation of a General Parabola having axis along the x-axis is given by y2=4ax

where a= distance between Vertex and Focus.

Here y coordinate in Focus and Vertex is the same.

Thus this parabola would be along direction of the x-axis.

Diatance between vertex and focus =(3(1))2+(22)2=4

thus equation of parabola is (y2)2=4.(4)(x(1))

i.e.(y2)2=16(x+1)

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