Equilibrium constants K-1-and K-2-for the following equilibria are NO-g- - -0-5O-2-g-K-1-NO-2-g-and 2NO-2-g-K-2- 2NO-g- - O-2-g-K2 - -1-K-1-K2 - K-12-K2 - -K-1-2-K2 - -1-K-12-

The correct option is D K2 = 1/K12 K_1 = [NO_2]/[NO][O_2]^0.5 and K_2 = [NO]^2[O_2]/[NO_2]^2 Or K_2 = 1/K_1^2 ...

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Effective Equilibrium Constant

Equilibrium c...

Question

Equilibrium constants $K_{1}$ and $K_{2}$ for the following equilibria are

$N O (g) + 0.5 O_{2} (g) \to K_{1} N O_{2} (g)$ and
$2 N O_{2} (g) \to K_{2} 2 N O (g) + O_{2} (g)$

K₂= 1/K₁

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K₂= K₁²

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K₂= (K₁)/2

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K₂= 1/K₁²

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Solution

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K_{1}

K_{2}

N O_{(g)} + \frac{1}{2} O_{2 (g)} ⇌ N O_{2 (g)}

2 N O_{2 (g)} ⇌ 2 N O_{(g)} + O_{2 (g)}

Equilibrium constants $K_{1}$ and $K_{2}$ for the following equilibria are

$N O (g) + 0.5 O_{2} (g) \to K_{1} N O_{2} (g)$ and
$2 N O_{2} (g) \to K_{2} 2 N O (g) + O_{2} (g)$

Equilibrium constants $K_{1}$ and $K_{2}$ for the following equilibria are

$N O (g) + 0.5 O_{2} (g) \to K_{1} N O_{2} (g)$ and
$2 N O_{2} (g) \to K_{2} 2 N O (g) + O_{2} (g)$

K_{1}

K_{2}

N O (g) + \frac{1}{2} O_{2}_{1} {N O}_{2} (g)

2 {N O}_{2} (g)_{2} 2 N O (g) + O_{2} (g)

K_{1}

K_{2}

N O (g) + \frac{1}{2} O_{2} (g) K_{1} ⇌ N O_{2} (g)

2 N O_{2} (g) K_{2} ⇌ 2 N O (g) + O_{2} (g)

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