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Standard XII

Chemistry

Equivalent, Molar Conductivity and Cell Constant

Equivalent co...

Question

Equivalent conductance of 1 M propanoic acid is 10 $o h m^{- 1} c m^{2} e q^{- 1}$ and that at infinite dilution 200 $o h m^{- 1} c m^{2} e q^{- 1}$ . The pH of the propanoic acid solution is:

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3.3

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1.3

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6.8

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Solution

The correct option is D 1.3
The degree of dissociation, $α$ = $\frac{Λ (e q u i v a l e n t c o n d u c t a n c e a t g i v e n d i l u t i o n)}{Λ_{\infty} (e q u i v a l e n t c o n d u c t a n c e a t g i v e n d i l u t i o n)}$

$α = \frac{10}{200} = 0.05$

$C H_{3} C H_{2} C O O H \to C H_{3} C H_{2} O O^{-} + H^{+}$

$C (1 - α)$ $C α$ $C α$

Given,
$C = 1 M$

$∴ C α = 0.05$

$p H = - l o g [H^{+}]$

$= - l o g [0.05]$

$= 1.3$

Hence, the correct option is $C$ .

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Equivalent conductance of 1 M propanoic acid is 10 ohm−1 cm2 eq−1 and that at infinite dilution 200 ohm−1 cm2 eq−1 . The pH of the propanoic acid solution is:

The correct option is D 1.3The degree of dissociation, α = Λ(equivalent conductance at given dilution)Λ∞(equivalent conductance at given dilution) α=10200=0.05CH3CH2COOH→CH3CH2OO−+H+C(1−α) Cα CαGiven, C=1M∴Cα=0.05pH=−log[H+] =−log[0.05] =1.3Hence, the correct option is C.

Equivalent conductance of 1 M propanoic acid is 10 $o h m^{- 1} c m^{2} e q^{- 1}$ and that at infinite dilution 200 $o h m^{- 1} c m^{2} e q^{- 1}$ . The pH of the propanoic acid solution is: