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Question

Equivalent weight of Cr2O72 (mol. wt. = M) in the following reaction is :
Cr2O72+6I+14H+2Cr3++3I2+7H2O

A
M6
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B
M3
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C
M2
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D
M
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Solution

The correct option is A M6
In acidic medium, the oxidation number of chromium atom decreases from +6 to +3.
The net decrease in the oxidation number per Cr atom is 3.
The net decrease in the oxidation number for two Cr atoms is 6.
Hence, the oxidation number of Cr2O72=M6.

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