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Question

Ethyl bromide and bromocyclohexane are treated with ammonia separately with ammonia, the products formed respectively are


A

Ethylamine, Cyclohexylamine

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B

Ethylene, Cyclohexane

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C

Ethylamine, Cyclohexene

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D

Ethylene, Cyclohexylamine

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Solution

The correct option is C

Ethylamine, Cyclohexene


Ethyl bromide being 10 alkyl halide, undergoes substitution reaction to give ethylamine whereas 20 halide like bromocyclohexane preferably undergoes dehydrohalogenation to give an alkene.


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