Ethyl bromide (or) chloride can be converted to butane in the presence of

{L i A l H}_{4}

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N a /

Dry ether

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alc.

K O H

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aq.

K O H

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Solution

The correct option is B $N a /$ Dry ether
Primary alkyl halides on reaction with $N a /$ dry ether (reducing agent) reduces alkyl halides to alkanes.
By Wurtz reaction of ethyl bromide with sodium metal:
$2 C H_{3} C H_{2} X + 2 N a / d r y e t h e r \to C H_{3} C H_{2} C H_{2} C H_{3} + 2 N a X$

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