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Question

Ethylene chloride and ethylidene chloride are isomers. Identify the correct statements.


A
Both the compounds from same product on treatment with alcoholic KOH.
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B
Both the compounds from same product on treatment with aq. NaoH.
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C
Both the compounds from same product on reduction.
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D
Both the compounds are optically active,
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Solution

The correct options are
A Both the compounds from same product on treatment with alcoholic KOH.
C Both the compounds from same product on reduction.
(A) Ethylene chloride and ethylidene chloride on treatment with alc. KOH show elimination reaction and ethyne as the product.
$$\underset{Ethylidene\  chloride}{CH_3−CHCl_2}\xrightarrow {Alc.KOH(excess)}CH≡CH$$

(B) Both these compounds from different products on treatment with aq. NaOH.
$$Cl−CH_2−CH_2Cl\xrightarrow{Aq.NaOH}\underset {Ethylene \ glycol}{HO−CH_2−CH_2−OH}$$

$$CH_3−CHCl_2\xrightarrow{Aq.NaOH}CH_3−CH(OH)_2\xrightarrow{−H_2O}\underset{ethanal}{CH_3CHO}$$

(c) Both these compounds form same products on reduction.

$$Cl−CH_2−CH_2−Cl\xrightarrow{Reduction}\underset{ethane}{H_3C−CH_3}+2HCl$$

$$CH_3−CHCl_2→ \underset{ethane}{H_3C−CH_3}+2HCl$$

(d) Both these compounds are optically inactive.

Chemistry

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