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Question

Euclid's Division Lemma states that for any two positive integers a and b, there exist unique integers q and r, such that a = bq + r, where
(a) 0 < r < b
(b) 0 ≤ r < b
(c) 0 < r ≤ b
(d) 1 < r < b

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Solution

(b) 0 ≤ r < b
On dividing a by b, let q be the quotient and r be the remainder.
Then, we have:
a = bq + r, where 0 ≤ r < b

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