Evaluate
$12 (2 x - 3 y)^{2} - 16 (3 y - 2 x)$

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Solution

$12 (2 x - 3 y)^{2} - 16 (3 y - 2 x) = 12 (3 y - 2 x)^{2} - 16 (3 y - 2 x)$
$= 4 (3 y - 2 x) (3 (3 y - 2 x) - 4)$
$= 4 (3 y - 2 x) (9 y - 6 x - 4)$

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Factorise:
$12 (2 x - 3 y)^{2} - 16 (3 y - 2 x)$

Factorization:

$9 (2 x - 3 y)^{2} - 12 (2 x - 3 y) (2 x + 3 y) + 4 (2 x + 3 y)^{2}$

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Factorize the given expression:

$9 (2 x - 3 y)^{2} - 12 (2 x - 3 y) (2 x + 3 y) + 4 (2 x + 3 y)^{2}$

\int_{1}^{2} (2 x + 5) d x

\int_{1}^{2} x^{2} d x

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