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Question

Using an identity, evaluate 166×94.


A

15604

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B

14551

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C

14562

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D

13552

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Solution

The correct option is A

15604


To evaluate : 166× 94

The average of 166 and 94
=166+942=130

Hence, 166× 94 can be written as
(130+36)(13036).

By applying the identity (a+b)(ab)=a2b2,

166×94=(130+36)(13036)
=1302362=169001296=15604


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