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Question

Evaluate ∣∣ ∣∣200920102011201020112012201120122013∣∣ ∣∣

A
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B
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C
0
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D
10
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Solution

The correct option is C 0
Given,
∣ ∣200920102011201020112012201120122013∣ ∣

Applying the following transformations C3C3C2;C2C2C1

we get,

∣ ∣200920102011111111∣ ∣
Now, again doing C2C2C3, we get

∣ ∣200920102011000111∣ ∣
Now, expanding along with C2 we get

∣ ∣200920102011000111∣ ∣=0

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