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Question

Evaluate : secθcosec(90θ)tanθcot(90θ)+sin255+sin235tan10tan20tan60tan70tan80

A
13
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B
23
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C
3
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D
1
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Solution

The correct option is B 23
secθcsc(90θ)tanθcot(90θ)+sin255+sin235tan10tan20tan60tan70tan80

=(secθ×secθ)(tanθ×tanθ)+sin255+cos255tan101tan10tan201tan20tan60

=(sec2θtan2θ)+sin255+cos255tan60

=1+13

=23

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