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Question

Evaluate (1+lnx)dx
(where C is constant of integration)

A
lnx+C
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B
xlnx+C
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C
x+C
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D
x+lnx+C
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Solution

The correct option is B xlnx+C
Let I=(1+lnx)dx
I=(x1x+lnx)dx
Clearly it is of the form (xf(x)+f(x))dx=xf(x)
where f(x)=lnx.
Hence, I=xlnx+C.

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