CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Evaluate dxx(1+x).

A
log(1+x)+c
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
2log(x)+c
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
6log(1+x2)+c
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
2log(1+x)+c
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D 2log(1+x)+c
Consider, I=dxx(1+x)

1+x=t dx2x=dt

I=2dtt

I=2ln(t)+c

I=2ln(1+x)+c.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Integration by Substitution
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon