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Question

Evaluate:
sin3xcos3xdx

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Solution

sin3xcos3xdx
we know 2 sin x cos x = sin 2x
(sinxcosx)3dx=18(2sinxcosx)3dx
18sin32xdx
we know sin3θ=3sinθ4sin3θ
sin3θ=3sinθsin3θ4
18×143sin2xsin6xdx
132[3cos2x2+cos6x6]
164[3cos2xcos6x3]

1208185_1361412_ans_7fbc1f3aa535464d8c8cd87e88439abd.jpg

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