CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Evaluate: limx0{sin(α+β)x+sin(αβ)x+sin2αx}cos2βxcos2αx

Open in App
Solution

limx0sin(α+β)x+sin(αβ)x+sin2αxcos2βxcos2αx

=limx0sin(α+β)x(α+β)×(α+β)+sin(αβ)x(αβ)×(αβ)+sin2αx2α×2αsin(α+β)sin(αβ)

=limx0sin(α+β)x(α+β)×(α+β)+sin(αβ)x(αβ)×(αβ)+sin2αx2α×2αsin(α+β)x(α+β)×(α+β)sin(αβ)(αβ)×(αβ)

=α+β+αβ+2α(α+β)(αβ)

=4αα2β2

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Principal Solution
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon