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Question

Evaluate e2xsinxdx.

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Solution

I=e2xsinxdx=?
I=e2xcosx+e2x(2)cosxdx
I=e2xcosx+2e2xsinx4e2xsinxdx
I=e2xcosx+2e2xsinx4I
5I=e2xcosx+2e2xsinx
I=15[2e2xsinxe2xcosx]=15e2x[2sinxcosx]


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