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Question

Evaluate
tan2θ+cot2θ+2=sec2θ+cosec2θ

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Solution

According to question,
tan2θ+cot2θ+2=sec2θ+cosec2θ
sec2θ+cosec2θtan2θcot2θ=2
LHS, sec2θtan2θ+cosec2θcot2θ
1+1
2=RHS
Hence proved


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