CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Evaluate the given integral.
x2+1x4+7x2+1dx

Open in App
Solution

I=(x2+1)dxx4+7x2+1

I=x2(1+1x2)dxx2(x2+7+1x2)

I=(1+1x2)dx(x2+7+1x2)

I=(1+1x2)dx(x2+1x2+7)

I=(1+1x2)dx(x2+1x22x2×1x2+2x2×1x2+7)

I=(1+1x2)dx(x1x)2+9

Let t=x1xdt=(1+1x2)dx

I=dtt2+9

=13tan1(t3)+c

=13tan1⎜ ⎜ ⎜x1x3⎟ ⎟ ⎟+c where t=x1x

=13tan1(x213x)+c

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Integration by Substitution
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon