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Question

Evaluate:y=limx0(sinx)tanx

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Solution

y=limx0(sinx)tanx
logy=limx0log((sinx)tanx)
=limx0logsinxcotx
Applying L Hospital Rule
logy=limx01sinx×cosxcsc2x
=limx0(sinxcosx)=0
y=e0=1


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