Events A and B are such that P(not A or not B) = 0.44. State whether A and B are mutually exclusive events. (Yes/No)

Yes

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is A
No

P(not A or not B) =P(A’ $\cup$ B’) = 0.44

P(A’ $\cup$ B’) = P((A $\cap$ B)’) = 0.44 ……………………… (1)

P(A $\cap$ B) = 1 – P((A $\cap$ B)’)

= 1- 0.44

= 0.56 ……………………………… (2)

Two events A and B are mutually exclusive if P(A $\cap$ B) = 0

Suggest Corrections

Similar questions

Q. Events E and F are such that P(not E or not F) = 0.25, State whether E and F are mutually exclusive.

Q. Events

E

and

F

are such that P(not E or not F)

= 0.25

State whether

E

and

F

are mutually exclusive

Events E and F are such that P(not E or Not F) = 0.25 state whether E and F are mutually exclusive.

Events A and B ar such that $P (A) = \frac{1}{2} P (B) = \frac{7}{12}$ and P (not A or not B) $= \frac{1}{4} .$ State whether A and B are independent?

Q. Three coins are tossed. Describe.
(i) two events A and B which are mutually exclusive.
(ii) three events A, B and C which are mutually exclusive and exhaustive.
(iii) two events A and B which are not mutually exclusive.
(iv) two events A and B which are mutually exclusive but not exhaustive.

Events A and B are such that P(not A or not B) = 0.44. State whether A and B are mutually exclusive events. (Yes/No)

The correct option is A No P(not A or not B) =P(A’∪B’) = 0.44 P(A’∪B’) = P((A∩B)’) = 0.44 ……………………… (1) P(A∩B) = 1 – P((A∩B)’) = 1- 0.44 = 0.56 ……………………………… (2) Two events A and B are mutually exclusive if P(A∩B) = 0