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Question

Examine the consistency of the system of equations

x+y+z=1,2x+3y+2z=2,ax+ay+2az=4

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Solution

The given system can be written as AX=B, where
A=111232aa2a.X=xyzB=124
Here, |A|=∣ ∣111232aa2a∣ ∣=1(6a2a)1(4a2a)+1(2a3a)
=4a2aa=4a3a=a0
A is non-singular. Therefore, A1 exists.
Hence, the given system of equations is consistent.


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