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Question

Examine the nature of the roots of the quadratic (bx)24(ax)(cx)=0 where a, b, c are real.

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Solution

The given equation can be written as 3x2[4(a+c)2b]x(b24ac)=0
Δ=[4(a+c)2b]2+12(b24ac)
=4[2(a+c)b]2+(3b212ac)
=4[2(a2+c2)+2ac+b24b(a+c)+3b212ac]
=16[a2+b2+c2abbcca]
=8[(ab)2+(bc)2+(ca)2]=+ive
Roots are real.

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