Expand the following with suitable identity
$(- 4 x + 2 y z)^{2}$ .

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Solution

Since $(a + b)^{2} = a^{2} + 2 a b + b^{2}$
$∴ (- 4 x + 2 y z)^{2} = (- 4 x)^{2} + 2 (- 4 x) (2 y z) + (2 y z)^{2}$
$= 16 x^{2} - 16 x y z + 4 y^{2} z^{2}$

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