Explain Halogenation reaction with conversion of $C H_{4}$ to $C C l_{4}$ in alkanes.

Open in App

Solution

Substitution reaction happens in which hydrogen atom in the Methane are replaced one at a time by chloride Ion or chlorine atom. a mixture of Methane and chlorine is exposed to a flame that explodes producing carbon and hydrogen , chlorine
$C H_{4} + C l_{2} + e n e r g y \to C H_{3} C l + H C l$
This is the halogenation reaction of methane into $C C l_{4}$
$C H_{3} - C l + C l Δ \to C H_{2} - C l_{2} + H C l$
$C H_{2} - C l_{2} + C l_{2} Δ \to C H - C l_{3} + H C l$
$C H - C l_{3} + C l Δ \to C - C l_{4} + H C l$

Suggest Corrections

Similar questions

C C l_{4}, C H C l_{3}

C H_{4}

Which of the following is formed in reaction mechanism of halogenation of alkanes in presence of UV light?

K O H

N a O H + C a O

K_{2} C r_{2} O_{7}

Join BYJU'S Learning Program