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Question

Explain hybridization of central atom in $$NO_3^-$$


Solution

Hybridisation $$=\dfrac { 1 }{ 2 } $$ (Valence electrons $$+$$ No. of Monovalent atoms $$-$$ Cationic charge $$+$$ Anionic charge)
For compound $${ NO }_{ 3 }^{ - }$$
$$=\dfrac { 1 }{ 2 } \left( 5+0-0+1 \right) =\dfrac { 6 }{ 2 } =3={ SP }^{ 2 }$$
Ans :- $${ sp }^{ 2 }$$ hybridisation.

Chemistry

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