Explain the oxidising power of $F, C l, B r, I$ on the basis of electrochemical series.

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Solution

According to electrochemical series reduction potentials are:
$F_{2} + 2 e^{-} \to 2 F^{-}; E_{0} = 2.87 V {C l}_{2} + 2 e^{-} \to 2 {C l}^{-}; E_{0} = 1.36 V {B r}_{2} + 2 e^{-} \to 2 {B r}^{-}; E_{0} = 1.08 V I_{2} + 2 e^{-} \to 2 I^{-}; E_{0} = 0.535 V$
Since reduction potential defines the tendency of a specie to get get reduce or its oxidising power. Therefore the oxidising power of halogen molecules will follow the order:
$F_{2}$ > $C l_{2}$ > $B r_{2}$ > $I_{2}$ .

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