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Question
Explain why free radical bromination of n-butane yields 2-bromobutane as the major product.
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Solution
Bromination of Alkyl halides is free radical Substitution reaction
n-Butane on brominatian two possibilite
(a) CH3−CH2−CH2−CH∘2+H∘
Then Br' combines to give possible products
(a) CH3−CH2−CH2−CH2+Br→CH2−CH2−CH2−CH−Br
(b) CH3−CH2−CH(Br)CH3
In above two reaction (b) is major
because secondary free radical is more Stable than primary free radical
∴ we will get 2 -bromo butane as the major product.
Then Br' combines to give possible products
(a) CH3−CH2−CH2−CH2+Br→CH2−CH2−CH2−CH−Br
(b) CH3−CH2−CH(Br)CH3
In above two reaction (b) is major
because secondary free radical is more Stable than primary free radical
∴ we will get 2 -bromo butane as the major product.
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