Exponential form of -3-3-3 is

The correct option is B ( 3)^3 The value of ( 3)^1×( 3)^1×( 3)^1 is =( 3)^1+1+1 =( 3)^3 Hence, option B is correct. ...

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Standard VIII

Mathematics

Exponents with Unlike Bases and Same Exponent

Exponential f...

Question

Exponential form of $(- 3) \times (- 3) \times (- 3)$ is

- 3^{3}

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(- 3)^{3}

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3^{3}

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(3)^{3}

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Solution

The correct option is B $(- 3)^{3}$
The value of ${(- 3)}^{1} \times {(- 3)}^{1} \times {(- 3)}^{1}$ is
$= {(- 3)}^{1 + 1 + 1}$
$= {(- 3)}^{3}$

Hence, option B is correct.

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Similar questions

Simplify and write in exponential form: $3^{3}$ x $3^{- 2}$ x $27^{2}$

Q. If

P = 5^{33} + 5^{33} + 5^{33} + 5^{33} + 5^{33}

and

Q = 3^{33} + 3^{33} + 3^{33}

and

P Q = 15^{x}

, then x equal to

(x + 3)^{3} = x^{3} + 3^{3} + 3 x (3) (x + 3)

Δ A B C,

X Y

is parallel to

A C

and

Area (Δ B X Y) : Area (□ A C Y X) = 1 : 2.

Then the ratio

\frac{A X}{A B}

equals

Given a = 6 + √3
⇒ (1/a) = 1 / (6 + √3)
Multiply and divide by (6 − √3)
⇒ (1/a) = (6− √3) / [(6 + √3)(6 − √3)]
⇒ (1/a) = (6 − √3) / [36 − 3]
⇒ (1/a) = (6− √3)/33
∴ a - (1/a) = (6 + √3) -(6 − √3)/33
= [33(6 + √3) - (6 - √3)]/33
= [32*6 + 34*√3]/33
= [192 + 34√3]/33

Answer : [192 + 34√3]/33

Why does 1/a come above

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Exponential form of (−3)×(−3)×(−3) is

The correct option is B (−3)3The value of (−3)1×(−3)1×(−3)1 is=(−3)1+1+1=(−3)3Hence, option B is correct.

Exponential form of $(- 3) \times (- 3) \times (- 3)$ is

The correct option is B $(- 3)^{3}$
The value of ${(- 3)}^{1} \times {(- 3)}^{1} \times {(- 3)}^{1}$ is
$= {(- 3)}^{1 + 1 + 1}$
$= {(- 3)}^{3}$

Hence, option B is correct.