Express the product of $2 x^{2} + 6 x - 8$ and $x + 3$ in standard form.

Open in App

Solution

To find the product:
The distributive law of real number and polynomial is :
$a (c + d) = a c + a d$
Use distributive property to multiply each term of of the first polynomial with the second in the expression $(2 x^{2} + 6 x - 8) (x + 3)$ .
$2 x^{3} + 6 x^{2} + 6 x^{2} + 18 x - 8 x - 24$
Now combine the like terms.
$2 x^{3} + 12 x^{2} + 10 x - 24$ .
Hence, the product in standard form is
$2 x cubed plus 12 x squared plus 10 x minus 24$ .

Suggest Corrections

Similar questions

5 {(x + y)}^{2} - 6 x - 6 y - 8

5 x^{3} - 6 x + 4 x^{2} + 8

Express the product of $3.2 \times 10^{6}$ and $4.1 \times 10^{- 1}$ in the standard form.

\frac{3 x^{2} + 8 x - 3}{2 x^{2} - x - 6}

\frac{x^{2} - 4}{x + 3}

Join BYJU'S Learning Program