$f : [- 4, 3) \to A, f (x) = x^{2} + 2$ is a function. Then which of the following represent's set $A$

[2, 18]

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[2, 11)

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[2, 18)

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[2, 11]

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Solution

The correct option is A $[2, 18]$
$f (x) = x^{2} + 2$ in $x \in [- 4, 3)$
$∵ x^{2} + 2 \geq 2$
Now, $x^{2} + 2 = 2$ at $x = 0 \in [- 4, 3)$
and $f (- 4) = 18, f (- 3) = 11$
$∴ f (x) \in [2, 18], \forall x \in [- 4, 3)$

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f:[−4,3)→A,f(x)=x2+2 is a function. Then which of the following represent's set A

The correct option is A [2,18]f(x)=x2+2 in x∈[−4,3) ∵x2+2≥2 Now, x2+2=2 at x=0∈[−4,3) and f(−4)=18,f(−3)=11 ∴f(x)∈[2,18], ∀ x∈[−4,3)

$f : [- 4, 3) \to A, f (x) = x^{2} + 2$ is a function. Then which of the following represent's set $A$

The correct option is A $[2, 18]$
$f (x) = x^{2} + 2$ in $x \in [- 4, 3)$
$∵ x^{2} + 2 \geq 2$
Now, $x^{2} + 2 = 2$ at $x = 0 \in [- 4, 3)$
and $f (- 4) = 18, f (- 3) = 11$
$∴ f (x) \in [2, 18], \forall x \in [- 4, 3)$