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Question

f(x)=log2(2log2(16sin2x+1)). What is its range?

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Solution

f(x)=log2(2log2(16sin2x+1))
=log2(2log(16[0,1]+1)) (sin2x is continuous increasing function)
=log2(2[0,log217]) (log2 is continuous increasing function)
log2(2log2(4),2) (log2 is also increasing function, 2>1)
=(,12] (as 2log217<0 taking log2(4)=0)


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