Factorise
$49 a^{2} b^{4} - 4 a^{2} b^{6}$

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Solution

$\begin{matrix} 49 a^{2} b^{4} - 4 a^{2} b^{6} {(7 a b^{2})}^{2} - {(4 a b^{3})}^{2} [a^{2} - b^{2} = (a - b) (a + b)] (7 a b^{2} - 4 a b^{3}) (7 a b^{2} + 4 a b^{3}) \end{matrix}$

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