Factorise:

$4 a^{2} - 12 a + 9 - 49 b^{2}$

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Solution

$4 a^{2} - 12 a + 9 - 49 b^{2} = [(2 a)^{2} - 2 (2 a) (3) + (3)^{2}] - (7 b)^{2} = [2 a - 3]^{2} - [7 b]^{2} = [2 a - 3 + 7 b] [2 a - 3 - 7 b]$

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Similar questions

4 a^{2} - 12 a + 9 - 49 b^{2}

4 a^{2} - 12 a + 9 - 49 b^{2}

Factorise:

$4 a^{2} - 49 b^{2} + 2 a - 7 b$

3 - 12 (a - b)^{2}

4 a^{2} - 9 b^{2} - 2 a - 3 b

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