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Question

Factorise    4a2b12a216b+48 



Your Answer
A

4xz

Correct Answer
B

4xy

Your Answer
C

4xz

Your Answer
D

4xyz


Solution

The correct option is C

4xy


Given 4a2b12a216b+48

Taking common factor as 4a2 from the first two terms and 16b as from the last two terms we get

4a2b12a216b+48 = 4a2(b3)16(b3)

= (4a216)(b3)

= (2a)2(4)2)(b3) ( converting in the form a2b2)

= (2a4)(2a+4)(b3))

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