The correct option is D (2x+ 3y)(2x 3y) 4x^2 9y^2 =(2x)^2 (3y)^2 , nbsp; Using a^2 b^2=(a+b)(a b) =(2x+ 3y)(2x 3y) ...

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Expansion of (x^2 - y^2)

Factorise 4x...

Question

Factorise
$4 x^{2} - 9 y^{2}$

(2x+ 3y)(2x-3y)

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(x+ 3y)(2x+3y)

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(4x+ y)(2x-3y)

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(4x+ 3y)(2x+3y)

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Solution

The correct option is D (2x+ 3y)(2x-3y)
$4 x^{2} - 9 y^{2}$
$= (2 x)^{2} - (3 y)^{2}$ , Using $a^{2} - b^{2} = (a + b) (a - b)$
$= (2 x + 3 y) (2 x - 3 y)$

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Factorization:

$9 (2 x - 3 y)^{2} - 12 (2 x - 3 y) (2 x + 3 y) + 4 (2 x + 3 y)^{2}$

Simplify: $(2 x - 3 y) (2 x + 3 y)$

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(2 x - 3 y) (2 x + 3 y) (4 x^{2} + 9 y^{2})

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