Factorise : $5 x^{2} - 16 x - 21$

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Solution

Given : $5 x^{2} - 16 x - 21$
We can further write it as
$5 x^{2} - 16 x - 21$ $= 5 x^{2} + 5 x - 21 x - 21$
by taking out the common terms
$5 x^{2} - 16 x - 21$ $= 5 x (x + 1) - 21 (x + 1)$
So we get,
$5 x^{2} - 16 x - 21$ $= (5 x - 21) (x + 1)$

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Similar questions

Factorise:
$5 x^{2} - 16 x - 21$

5 x^{2} = - 16 x - 12

A = 5 x^{2} - 16 x - 21

B = 3 (x + 2)^{2} - 5 (x + 2) + 2

A

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