Factorise: $6 a b - b^{2} + 12 a c - 2 b c$

Open in App

Solution

Given expression is $6 a b - b^{2} + 12 a c - 2 b c$
It can be written as $6 a b - b^{2} + 12 a c - 2 b c = b (6 a - b) + 2 c (6 a - b) = (b + 2 c) (6 a - b)$
Thus factors are, $(b + 2 c), (6 a - b)$ .

Suggest Corrections

Similar questions

\frac{6 a b - b^{2} + 12 a c - 2 b c}{b + 2 c}

Divide (6 a b - b^{2} + 12 a c - 2 b c) by (b + 2 c)

(6 a b - b^{2} + 12 a c - 2 b c) d i v i d e d b y (6 a - b)

The quotient when $6 a b - b^{2} + 12 a c - 2 b c$ is divided by $(6 a - b)$ is ___

6 a b - b^{2} + 12 a c - 2 b c

Join BYJU'S Learning Program