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Question

Factorise : 9a2+3a8b64b2

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Solution

Given : 9a2+3a8b64b2

We can write it as
9a2+3a8b64b2=9a264b2+3a8b
So we get
9a2+3a8b64b2=(3a)2(8b)2+(3a8b)
Based on the equation a2b2=(a+b)(ab)
We get,
9a2+3a8b64b2=(3a+8b)(3a8b)+(3a8b)
Taking (3a8b) as common

9a2+3a8b64b2=(3a8b)(3a+8b+1)

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