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Question

Factorise:
9a2+6a+136b2


Solution

9a2+6a+136b2

=(3a)2+2×3a×1+12(6b)2=(3a+1)2(6b)2[a2+2ab+b2=(a+b)2]=(3a+16b)(3a+1+6b)[a2b2=(ab)(a+b)]=(3a6b+1)(3a+6b+1)


Mathematics
Secondary School Mathematics IX
Standard IX

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