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Question

Factorise (a2+1)b2b4a2.


  1. (a1)(b1)(b+1)

  2. (a1)(b1)

  3. (a1)(a+1)(b1)(b+1)

  4. (a+1)(b1)(b+1)


Solution

The correct option is C

(a1)(a+1)(b1)(b+1)


(a2+1)b2b4a2
=a2b2+b2b4a2   
              (Opening the brackets)
=a2b2a2b4+b2      
              (Re-grouping the terms)
=a2(b21)1(b21)       
              (Taking the common factors)
=(a21)(b21)
=(a1)(a+1)(b1)(b+1)     
               [x2y2=(xy)(x+y)]

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