Byju's Answer
Standard IX
Mathematics
(x³±y³)
Factorise : ...
Question
Factorise :
(
a
2
−
b
2
)
(
a
2
+
a
b
+
b
2
)
−
a
3
+
b
3
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Solution
We have,
(
a
2
−
b
2
)
(
a
2
+
a
b
+
b
2
)
−
a
3
+
b
3
⇒
(
a
2
−
b
2
)
(
a
2
+
a
b
+
b
2
)
−
(
a
3
−
b
3
)
⇒
(
a
−
b
)
(
a
+
b
)
(
a
2
+
a
b
+
b
2
)
−
(
a
−
b
)
(
a
2
+
a
b
+
b
2
)
⇒
(
a
+
b
−
1
)
(
a
−
b
)
(
a
2
+
a
b
+
b
2
)
Hence, this is the answer.
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