Factorise
$a^{3} + 0.008$

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Solution

$a^{3} + 0.008 = a^{3} + {0.2}^{3} = (a + 0.2) (a^{2} - a \times 0.2 + {0.2}^{2}) = (a + 0.2) (a^{2} - 0.2 a + 0.04)$

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