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Question

Factorise a327.

A
=(a3)(a2+5a+9)
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B
=(a+3)(a2+5a+9)
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C
(a3)(a25a+9)
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D
(a3)(a3+5a+9)
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Solution

The correct option is A =(a3)(a2+5a+9)
a327
=a333
{a3b3=(ab)(a2+ab+b2}
a=a and b=3
Hence a327=(a3)(a2+3a+9)


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