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Question

Factorise:

a67a38


Solution

a67a38=a6+a38a38=a3(a3+1)8(a3+1)=(a38)(a3+1)=[(a)3(2)3][(a)3+(1)3]=(a2)(a2+2a+4)(a+1)(a2a+1)


Mathematics
Concise Mathematics
Standard IX

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