Factorise: $a^{2} + 11 a + 24$

(a + 6) (a + 4)

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(a - 8) (a + 3)

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(a + 8) (a - 3)

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(a + 8) (a + 3)

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Solution

The correct option is D $(a + 8) (a + 3)$
$a^{2} + 11 a + 24$
Here, $24$ should be split in $2$ parts such that their sum is $11$ .
i.e. $8 \times 3 = 24$ and $8 + 3 = 11$

$∴ a^{2} + 11 a + 24$
$= a^{2} + 8 a + 3 a + 24$
$= a (a + 8) + 3 (a + 8)$
$= (a + 8) (a + 3)$

So, option D is correct.

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